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OUPower.com • View topic - 12V DC input, 330V DC output...

12V DC input, 330V DC output...

Here we will discuss many topics on electronic designs and circuits for various functions. PIC Chip programming has enormous potential in so many applications, that will be included in this forum as well.

12V DC input, 330V DC output...

Postby resident_genius » Thu Aug 27, 2009 1:39 am

where is the line between tinkerer and scientist, scientist and madman, madman and genius?

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Postby resident_genius » Thu Aug 27, 2009 1:42 am

Image

this is the possible circuit.....is this feasible? more details in my project folder.....
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Postby resident_genius » Thu Aug 27, 2009 1:44 am

lol i realize i drew in my diodes incorrectly..... but u get the idea....
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Postby Jehu » Thu Aug 27, 2009 1:54 am

Yeah, I think the rectifier should go before the multiplier, if that's what you were refering to. Otherwise, it looks like most other multiplier ciruits I've seen.
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Postby resident_genius » Thu Aug 27, 2009 2:54 am

ah, a valid point! much easier to find a rectifier built for 110V. anyone take a stab at this? if my 110 invert is rated @ 200 watts, that means it'd output 1.8 amps....1.8 amps divided by three is just over half an amphere.....is this going to charge up the caps in any amount of reasonable time?

basically, i am charging as large of a bank of 330V capacitors as possible, probably in the 25-30 qty range. each cap is 120uF, so @ qty/25, thats 3000uF @ 330V.
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Postby Jehu » Thu Aug 27, 2009 7:19 am

It's not the Current it supplies that will make any difference, even the voltage doesn't mean squat. It all depends on the resistance and te capacitance.

t=RC. so one time constant is equal to the resistance of the circuit (in Ohms) multiplied by the capacitance (in Farads). Multiply this by 5 to get the total time to charge up a capacator in a circuit.

So current and voltage really have no or little bearing on how fast your cap bank charges.
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Postby resident_genius » Thu Aug 27, 2009 11:05 am

damn, you see- i had googled everything i could think of, wondering if there was a formula for how long it would take to charge the cap bank. so i would have to hook up all thirty caps in parallel, measure the resistance of the circuit then apply to the formula? humm. im going to have to find someone with a good multimeter.
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Postby Jehu » Thu Aug 27, 2009 8:29 pm

Well, from memory it's only the first part of the circuit you have to worry about. basically from the inverter to the end of the cap bank as you would have a switch to trigger the discharge into the coil. So if you can make the charging stage as low resistance as possible, you will be able to decrease the charging time.

Now with how the caps are setup being wired in series in the multiplier circuit, this will also lower the capacitance while increasing the voltage. Now due to the decrease in capacitance, the charging time is reduced again, but also the final punch that the cap bank can deliver. I suppose this is ok if you are using the multiplier to charge a parralel cap bank, as the multiplier only really steps up the voltage but then you still have the problem of the time to charge the parrallel bank. And in this case you would be increasing the resistance again. Humm.

At this stage it makes me think that the flyback would be the better option, as long as the secondary coil doesn't have a huge resistance........
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Postby resident_genius » Fri Aug 28, 2009 11:42 pm

where is the line between tinkerer and scientist, scientist and madman, madman and genius?

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Inverter

Postby Katisa » Wed Sep 09, 2009 2:57 pm

Gatvol
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Postby resident_genius » Sat Sep 12, 2009 12:22 am

where is the line between tinkerer and scientist, scientist and madman, madman and genius?

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Postby AlaskaStar » Sat Sep 12, 2009 1:59 am

"Do we exist, or are we just an existence?"
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Postby resident_genius » Sat Sep 12, 2009 8:33 am



i know im linking to another forum, but if anyone else wants to read up on the M.E.G. transformer.....
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