I think that is wrong if we compare our gas production with Faraday's low.
We must calculate using hydrogen energy.
For exs.
If we have good production of 2Wh/L,that means 2KWh for 1000 lit,or 1 cubic meter of Oxyhydrogen,that means 3KWh for 1 cubic meter of hydrogen -1000 lit.
When 1000L of hydrogen is burning produce 3,33 or 3.5 KWh of energy.
That means we must compare our 3KWh with 3.33 or 3.5KWh.
If compare with 3.33KWh our electrolyser efficiency is 91%,and if compare with 3.5KWh our elecrtolyser has efficiency of 86%.
If we compare with Faraday's low our efficiency is aprox. 150%
