If you did read it and not forgot everything, you would have noted that extractable energy is dependant on
1. Size of capacitors
2. Reference voltage
This means: if you just use a 9 Volt battery block as a non destructed reference voltage, you would gain more power from it if you used LARGE capacitors (large would mean here: in the range of Farads) Such capacitors are today available as "Gold Caps" ( circa 5 Volt but low current) or "Super Caps" (around 2 Volt but capable of very high currents, theoretically in the hundreds Ampere range)
Or you use smaller caps but higher voltage, in the range of hundreds of volts. Super Caps in the high Volt range are not (yet) available let alone effordable.
I did some pre-run tests with this device and am still learning to exactly duplicate the given scenario.
I am very grateful that somebody is there who gives such detailed guidelines to follow.
Hint:
If you use a white LED as a current-sensor, you are able to "read" currents in the range from ca. 3 micro Ampere to around 100 milli Ampere (shorttime) or 20 mA (continuosly)
Never hook an LED directly to a charged capacitor, it will be destoyed in milliseconds. Always use a resistor in series to the LED, even if only 20 Ohm.
WiLiStatistics: Posted by WiLi — Mon Nov 27, 2006 3:58 pm
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