by spencyg » Tue Mar 06, 2007 5:00 pm
I just ordered my electrode material. I have 10 pcs of 7x8 16 ga 316, and 2 pcs of 7x16 16 ga 316. I figured with the gaskets (hypalon 1/8"), and the non-flooded zone at the top of the plates, the 7x8 will give me an honest 6x6 cell surface area, and the endplates are a tad larger to allow me to blast in some electrical tabs with the CNC mill. I did order 1 extra internal plate (shooting for 10 cells @ 14V) in case of a programming error with the gas and water add port drilling cycle at the top of each plate.
Now...please observe my math and tell me what you think:
At 1/4 amp per square inch, I'll be running (6x6)*(10 cells)*(0.25A/in2) = 90A @ 1.4V = 126 watts. Is this right, or should it be 90A @ 14v? If so, thats 1260 watts. Scenario "A" means 9A of draw @ 14V. Scenario B means 90A @ 14V. I like A better. When I install this system in the truck, I should be just fine with my stock alternator and a dual battery system assuming A is correct. If I need to provide 90A to this system, than I'm looking at a second alternator.
Spence