Anything wrong with this single cell design?

[Pinhead]

From what I've gathered so far in reading around the forum, efficiency of a DC cell has a lot to do with surface area of the electrodes, spacing between the electrodes, the number of cells (in series), and the electrolyte/catalyst.

This drawing is a single cell design. In this design, the surface area of the electrodes are vastly increased. The positive electrode would either be stainless steel bolts next to eachother to make a circle (the small black dots) or could be replaced with a stainless steel screen/mesh. The center electrode could be either a SS tube or bolt. The center tube/bolt and outer SS tube would be negative (-) electrodes and the wire mesh/concentric bolts would make up the positive (+) electrode.The outer tube would also be the outside wall of the cell. It would look much like the Mag Drive from the outside.(http://www.fuel-from-water.com/)

Outside tube=4" Diameter=12.57in^2
Inside Bolt=0.5" Diameter=0.196in^2
12.57-.196=12.374in^2
12.375/2=6.187in^2 = Half of total area
Pi*r^2=6.187
6.187/Pi=1.969
Sqrt(1.969)=1.403=R= 2.806 D=Positive Electrode Diameter

If the outside tube has a 4 inch diameter and the center bolt has a 1/2 inch diameter, than the positive electrode should have a 2.8 inch diameter to keep the same volume of water on either side of the positive electrode(s). (Correct me if my math is off).

This is a single cell unit, so to further increase efficiency it woutld either be run on approximately 2 volts or run in series with 6 similar cells on 12 volts (or 7 due to 14.4v charging of the alternator).

[Bob Boyce]

There are a few very obvious problems with that design besides the complexities of assembly.

First and foremost would be the unequal surface areas between inner and outer electrodes. Tubes are known to cause a great differential.

Second. The rods in between have surface area all around, but only the surfaces facing the opposite polarity are reactive. Almost half of each rod surface would not be active or count as effective surface area. Just because it is there does not mean it will conduct evenly into the solution.

Third. The field of the inner part of the cell would buck the field of the outer part of the cell, further reducing efficiency.

Bob